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cfta streptococci
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@ -25,9 +25,9 @@ To split ages, the input can be:
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\item{A character:}
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\itemize{
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\item{\code{"children"}, equivalent of: \code{c(0, 1, 2, 4, 6, 13, 18)}. This will split on 0, 1, 2-3, 4-5, 6-12, 13-17 and 18+.}
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\item{\code{"elderly"} or \code{"seniors"}, equivalent of: \code{c(65, 75, 85, 95)}. This will split on 0-64, 65-74, 75-84, 85-94 and 95+.}
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\item{\code{"fives"}, equivalent of: \code{1:24 * 5}. This will split on 0-4, 5-9, 10-14, 15-19 and so forth, until 120.}
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\item{\code{"tens"}, equivalent of: \code{1:12 * 10}. This will split on 0-9, 10-19, 20-29 and so forth, until 120.}
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\item{\code{"elderly"} or \code{"seniors"}, equivalent of: \code{c(65, 75, 85)}. This will split on 0-64, 65-74, 75-84, 85+.}
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\item{\code{"fives"}, equivalent of: \code{1:20 * 5}. This will split on 0-4, 5-9, 10-14, ..., 90-94, 95-99, 100+.}
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\item{\code{"tens"}, equivalent of: \code{1:10 * 10}. This will split on 0-9, 10-19, 20-29, ... 80-89, 90-99, 100+.}
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}
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}
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}
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@ -46,11 +46,11 @@ age_groups(ages, 50)
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age_groups(ages, c(20, 50))
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# split into groups of ten years
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age_groups(ages, 1:12 * 10)
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age_groups(ages, 1:10 * 10)
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age_groups(ages, split_at = "tens")
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# split into groups of five years
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age_groups(ages, 1:24 * 5)
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age_groups(ages, 1:20 * 5)
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age_groups(ages, split_at = "fives")
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# split specifically for children
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@ -1,5 +1,5 @@
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% Generated by roxygen2: do not edit by hand
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% Please edit documentation in R/mo.R, R/mo_history.R
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% Please edit documentation in R/mo.R
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\name{as.mo}
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\alias{as.mo}
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\alias{mo}
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@ -7,7 +7,6 @@
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\alias{mo_failures}
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\alias{mo_uncertainties}
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\alias{mo_renamed}
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\alias{clean_mo_history}
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\title{Transform to microorganism ID}
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\usage{
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as.mo(x, Becker = FALSE, Lancefield = FALSE, allow_uncertain = TRUE,
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@ -20,8 +19,6 @@ mo_failures()
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mo_uncertainties()
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mo_renamed()
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clean_mo_history(...)
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}
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\arguments{
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\item{x}{a character vector or a \code{data.frame} with one or two columns}
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