Split ages into age groups defined by the split parameter. This allows for easier demographic (antimicrobial resistance) analysis.
age_groups(x, split_at = c(12, 25, 55, 75), na.rm = FALSE)
Arguments
| x | age, e.g. calculated with |
|---|---|
| split_at | values to split |
| na.rm | a logical to indicate whether missing values should be removed |
Value
Ordered factor
Details
To split ages, the input for the split_at parameter can be:
A numeric vector. A vector of e.g.
c(10, 20)will split on 0-9, 10-19 and 20+. A value of only50will split on 0-49 and 50+. The default is to split on young children (0-11), youth (12-24), young adults (25-54), middle-aged adults (55-74) and elderly (75+).A character:
"children"or"kids", equivalent of:c(0, 1, 2, 4, 6, 13, 18). This will split on 0, 1, 2-3, 4-5, 6-12, 13-17 and 18+."elderly"or"seniors", equivalent of:c(65, 75, 85). This will split on 0-64, 65-74, 75-84, 85+."fives", equivalent of:1:20 * 5. This will split on 0-4, 5-9, 10-14, ..., 90-94, 95-99, 100+."tens", equivalent of:1:10 * 10. This will split on 0-9, 10-19, 20-29, ..., 80-89, 90-99, 100+.
Stable lifecycle
The lifecycle of this function is stable. In a stable function, major changes are unlikely. This means that the unlying code will generally evolve by adding new arguments; removing arguments or changing the meaning of existing arguments will be avoided.
If the unlying code needs breaking changes, they will occur gradually. For example, a parameter will be deprecated and first continue to work, but will emit an message informing you of the change. Next, typically after at least one newly released version on CRAN, the message will be transformed to an error.
Read more on our website!
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See also
To determine ages, based on one or more reference dates, use the age() function.
Examples
ages <- c(3, 8, 16, 54, 31, 76, 101, 43, 21) # split into 0-49 and 50+ age_groups(ages, 50) # split into 0-19, 20-49 and 50+ age_groups(ages, c(20, 50)) # split into groups of ten years age_groups(ages, 1:10 * 10) age_groups(ages, split_at = "tens") # split into groups of five years age_groups(ages, 1:20 * 5) age_groups(ages, split_at = "fives") # split specifically for children age_groups(ages, "children") # same: age_groups(ages, c(1, 2, 4, 6, 13, 17)) # \donttest{ # resistance of ciprofloxacine per age group library(dplyr) example_isolates %>% filter_first_isolate() %>% filter(mo == as.mo("E. coli")) %>% group_by(age_group = age_groups(age)) %>% select(age_group, CIP) %>% ggplot_rsi(x = "age_group", minimum = 0) # }