AMR/inst/tinytest/test-age.R

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# ==================================================================== #
# TITLE #
# Antimicrobial Resistance (AMR) Data Analysis for R #
# #
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# SOURCE #
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# https://github.com/msberends/AMR #
# #
# LICENCE #
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# (c) 2018-2022 Berends MS, Luz CF et al. #
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# Developed at the University of Groningen, the Netherlands, in #
# collaboration with non-profit organisations Certe Medical #
# Diagnostics & Advice, and University Medical Center Groningen. #
# #
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# This R package is free software; you can freely use and distribute #
# it for both personal and commercial purposes under the terms of the #
# GNU General Public License version 2.0 (GNU GPL-2), as published by #
# the Free Software Foundation. #
# We created this package for both routine data analysis and academic #
# research and it was publicly released in the hope that it will be #
# useful, but it comes WITHOUT ANY WARRANTY OR LIABILITY. #
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# #
# Visit our website for the full manual and a complete tutorial about #
# how to conduct AMR data analysis: https://msberends.github.io/AMR/ #
# ==================================================================== #
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expect_equal(age(x = c("1980-01-01", "1985-01-01", "1990-01-01"),
reference = "2019-01-01"),
c(39, 34, 29))
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expect_equal(age(x = c("2019-01-01", "2019-04-01", "2019-07-01"),
reference = "2019-09-01",
exact = TRUE),
c(0.6656393, 0.4191781, 0.1698630),
tolerance = 0.001)
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expect_error(age(x = c("1980-01-01", "1985-01-01", "1990-01-01"),
reference = c("2019-01-01", "2019-01-01")))
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expect_warning(age(x = c("1980-01-01", "1985-01-01", "1990-01-01"),
reference = "1975-01-01"))
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expect_warning(age(x = c("1800-01-01", "1805-01-01", "1810-01-01"),
reference = "2019-01-01"))
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expect_equal(length(age(x = c("2019-01-01", NA), na.rm = TRUE)),
1)
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ages <- c(3, 8, 16, 54, 31, 76, 101, 43, 21)
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expect_equal(length(unique(age_groups(ages, 50))),
2)
expect_equal(length(unique(age_groups(ages, c(50, 60)))),
3)
expect_identical(class(age_groups(ages, "child")),
c("ordered", "factor"))
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expect_identical(class(age_groups(ages, "elderly")),
c("ordered", "factor"))
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expect_identical(class(age_groups(ages, "tens")),
c("ordered", "factor"))
expect_identical(class(age_groups(ages, "fives")),
c("ordered", "factor"))
expect_equal(length(age_groups(c(10, 20, 30, NA), na.rm = TRUE)),
3)