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arbiter tree with arbiters, not tested

This commit is contained in:
alexmadison 2022-03-03 11:56:34 +01:00
parent d0a2fff096
commit af52c688a3
1 changed files with 111 additions and 7 deletions
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118
dataflow_neuro/coders.act
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@ -87,13 +87,13 @@ namespace tmpl {
bitval = (i & ( 1 << j )) >> j; // Get binary digit of integer i, column j bitval = (i & ( 1 << j )) >> j; // Get binary digit of integer i, column j
[bitval = 1 -> [bitval = 1 ->
atree_x[i].in[j] = addr_buf.out.d.d[j].t; atree_x[i].in[j] = addr_buf.out.d.d[j].t;
[]bitval = 0 -> []bitval = 0 ->
atree_x[i].in[j] = addr_buf.out.d.d[j].f; atree_x[i].in[j] = addr_buf.out.d.d[j].f;
[]bitval >= 2 -> {false : "fuck"}; []bitval >= 2 -> {false : "fuck"};
] ]
atree_x[i].out = outx[i]; atree_x[i].out = outx[i];
) )
) )
andtree<NyC> atree_y[Ny]; andtree<NyC> atree_y[Ny];
(k:0..Ny-1:atree_y[k].supply = supply;) (k:0..Ny-1:atree_y[k].supply = supply;)
@ -102,16 +102,120 @@ namespace tmpl {
bitval = (i & ( 1 << j )) >> j; // Get binary digit of integer i, column j bitval = (i & ( 1 << j )) >> j; // Get binary digit of integer i, column j
[bitval = 1 -> [bitval = 1 ->
atree_y[i].in[j] = addr_buf.out.d.d[j+NxC].t; atree_y[i].in[j] = addr_buf.out.d.d[j+NxC].t;
[]bitval = 0 -> []bitval = 0 ->
atree_y[i].in[j] = addr_buf.out.d.d[j+NxC].f; atree_y[i].in[j] = addr_buf.out.d.d[j+NxC].f;
] ]
atree_y[i].out = outy[i]; atree_y[i].out = outy[i];
) )
) )
} }
/*
* Build an arbiter_handshake tree.
*/
export template<pint N>
defproc arbtree (a1of1 in[N]; a1of1 out; power supply)
{
bool tout;
{ N > 0 : "What?" };
pint i, end, j;
i = 0;
end = N-1;
pint arbCount;
arbCount = 0;
/* Pre"calculate" the number of C cells required, look below if confused */
*[ i != end ->
j = 0;
*[ i <= end ->
j = j + 1;
[i = end ->
i = end+1;
[] i+1 = end ->
i = end+1;
arbCount = arbCount +1;
[] else ->
i = i + 2;
arbCount = arbCount +1;
]
]
/*-- update range that has to be combined --*/
// i = end+1;
end = end+j;
]
/* array that holds ALL the nodes in the completion tree */
a1of1 tmp[end+1];
// Connecting the first nodes to the input
(l:N:
tmp[l] = in[l];
)
/* array to hold the actual C-elments, either A2C or A3C */
[arbCount > 0 ->
arbiter_handshake arbs[arbCount];
]
(h:arbCount:arbs[h].supply = supply;)
/* Reset the variables we just stole lol */
i = 0;
end = N-1;
j = 0;
pint arbIndex = 0;
/* Invariant: i <= end */
*[ i != end ->
/*
* Invariant: tmp[i..end] has the current signals that need to be
* combined together, and "isinv" specifies if they are the inverted
* sense or not
*/
j = 0;
*[ i <= end ->
/*-- there are still signals that need to be combined --*/
j = j + 1;
[ i = end ->
/*-- last piece: pipe input through to next layer --*/
tmp[end+j] = tmp[i];
i = end+1;
[] i+1 = end ->
/*-- last piece: use either a 2 input C-element --*/
arbs[arbIndex].in1 = tmp[i];
arbs[arbIndex].in2 = tmp[i+1];
arbs[arbIndex].out = tmp[end+j];
arbIndex = arbIndex +1;
i = end+1;
[] else ->
/*-- more to come; so use a two input C-element --*/
arbs[arbIndex].in1 = tmp[i];
arbs[arbIndex].in2 = tmp[i+1];
arbs[arbIndex].out = tmp[end+j];
arbIndex = arbIndex +1;
i = i + 2;
]
]
/*-- update range that has to be combined --*/
i = end+1;
end = end+j;
j = 0;
]
out = tmp[end];
}
} }
} }