arbiter init with or2s
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@ -416,5 +416,117 @@ defproc sigbuf (bool? in; bool! out[N]; power supply)
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(i:1..N-1:out[i]=out[0];)
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(i:1..N-1:out[i]=out[0];)
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}
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}
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/*
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* Build a completion tree using a combination of 2-input and 3-input
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* arbiters
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*/
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export template<pint N>
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defproc arbtree (bool? in[N]; bool! out; power supply)
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{
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bool tout;
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{ N > 0 : "What?" };
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pint i, end, j;
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i = 0;
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end = N-1;
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pint arbCount;
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arbCount = 0;
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/* Pre"calculate" the number of C cells required, look below if confused */
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*[ i != end ->
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j = 0;
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*[ i <= end ->
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j = j + 1;
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[i = end ->
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i = end+1;
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[] i+1 = end ->
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i = end+1;
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arbCount = arbCount +1;
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[] else ->
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i = i + 2;
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arbCount = arbCount +1;
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]
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]
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/*-- update range that has to be combined --*/
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// i = end+1;
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end = end+j;
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]
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/* array that holds ALL the nodes in the completion tree */
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bool tmp[end+1];
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// Connecting the first nodes to the input
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(l:N:
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tmp[l] = in[l];
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)
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/* array to hold the actual C-elments, either A2C or A3C */
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[arbCount > 0 ->
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OR2_X1 arbs[arbCount];
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]
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(h:arbCount:arbs[h].vdd = supply.vdd;)
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(h:arbCount:arbs[h].vss = supply.vss;)
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/* Reset the variables we just stole lol */
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i = 0;
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end = N-1;
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j = 0;
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pint arbIndex = 0;
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/* Invariant: i <= end */
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*[ i != end ->
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/*
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* Invariant: tmp[i..end] has the current signals that need to be
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* combined together, and "isinv" specifies if they are the inverted
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* sense or not
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*/
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j = 0;
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*[ i <= end ->
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/*-- there are still signals that need to be combined --*/
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j = j + 1;
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[ i = end ->
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/*-- last piece: pipe input through to next layer --*/
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tmp[end+j] = tmp[i];
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i = end+1;
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[] i+1 = end ->
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/*-- last piece: use either a 2 input C-element --*/
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arbs[arbIndex].a = tmp[i];
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arbs[arbIndex].b = tmp[i+1];
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arbs[arbIndex].y = tmp[end+j];
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arbIndex = arbIndex +1;
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i = end+1;
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[] else ->
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/*-- more to come; so use a two input C-element --*/
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arbs[arbIndex].a = tmp[i];
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arbs[arbIndex].b = tmp[i+1];
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arbs[arbIndex].y = tmp[end+j];
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arbIndex = arbIndex +1;
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i = i + 2;
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]
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]
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/*-- update range that has to be combined --*/
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i = end+1;
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end = end+j;
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j = 0;
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]
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out = tmp[end];
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}
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}}
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}}
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