removed arbiter_tree from primitives because is already in coders
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@ -507,122 +507,8 @@ namespace tmpl {
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BUF_X1 reset_buf(.a=reset_B, .y=_reset_BX,.vdd=supply.vdd,.vss=supply.vss);
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BUF_X1 reset_buf(.a=reset_B, .y=_reset_BX,.vdd=supply.vdd,.vss=supply.vss);
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}
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}
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// A tree composed by arbiters. The first layer takes N signals
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export template<pint N>
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defproc arbiter_tree(a1of1 in[N]; a1of1 out; power supply)
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{
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bool tout;
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{ N > 0 : "Invalid N, should be greater than 0" };
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/* We calculate here how many arbiters we need to create for the full tree */
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pint inputs_in_layer, end, elements_in_layer;
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pint odd_element_idx = 0;
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pint odd_element_flag = 0;
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inputs_in_layer = 0;
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end = N-1;
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pint element_counter = 0;
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// Here we start a for loop to count the elements in the tree
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// The loop iterates for every successive layer
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// i is the variable used to iterate the inputs,
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// j counts the elements in the layer
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*[ inputs_in_layer != end ->
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elements_in_layer = 0; // At every layer the counter of the elements is resetted
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*[ inputs_in_layer < end ->
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[ inputs_in_layer + 1 >= end ->
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//In this case, the number of input is even: the layer finishes
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inputs_in_layer = end;
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odd_element_flag = 0;
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[] inputs_in_layer + 2 >= end ->
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//In this case, we arrived at the last input, this means the inputs are odd
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//We need to save the odd input index and move it to the next layer,
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//up to when the resulting number is even
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odd_element_idx = end;
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odd_element_flag = 1;
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inputs_in_layer = end;
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[] else ->
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//If we are not close to the end, analyzes the next two inputs
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inputs_in_layer = inputs_in_layer +2;
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]
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elements_in_layer = elements_in_layer + 1; //At every step the elements count is updated
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]
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//Move the inputs_in_layer to the next layer
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//Increase the end to account for the next layer elements
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//If there was an odd element, count it also in the end
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inputs_in_layer = end + 1;
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end = end + elements_in_layer + odd_element_flag;
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element_counter = element_counter + elements_in_layer;
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]
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{ element_counter = 4 : "Michele you did wrong" };
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// Creating the elements of the tree
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arbiter_handshake arb_array[element_counter];
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(i:element_counter:arb_array[i].supply = supply;)
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// These are the wires that connect one element of the tree to the others
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a1of1 channels[element_counter*2];
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//Connecting the first channels to the inputs
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(i:N:channels[i] = in[i];)
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channels[element_counter*2-1] = out;
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//Now we redo the for loop but here to assign the channels to the elements
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odd_element_idx = 0;
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odd_element_flag = 0;
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inputs_in_layer = 0;
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end = N-1;
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{ end=4 : "Michele you did wrong" };
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// Here we start a for loop to count the elements in the tree
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// The loop iterates for every successive layer
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// i is the variable used to iterate the inputs,
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// j counts the elements in the layer
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*[ inputs_in_layer != end ->
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elements_in_layer = 0; // At every layer the counter of the elements is resetted
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*[ inputs_in_layer < end ->
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[ inputs_in_layer + 1 >= end ->
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//In this case, the number of input is even: the layer finishes
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[ odd_element_flag >= 1 ->
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arb_array[elements_in_layer].in1 = channels[inputs_in_layer];
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arb_array[elements_in_layer].in2 = channels[odd_element_idx];
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[] else ->
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arb_array[elements_in_layer].in1 = channels[inputs_in_layer];
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arb_array[elements_in_layer].in2 = channels[inputs_in_layer+1];
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]
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inputs_in_layer = end;
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odd_element_flag = 0;
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[] inputs_in_layer + 2 >= end ->
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//In this case, we arrived at the last input, this means the inputs are odd
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//We need to save the odd input index and move it to the next layer,
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//up to when the resulting number is even
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odd_element_idx = end;
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odd_element_flag = 1;
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{ end<8 : "Michele you did wrong" };
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{ odd_element_idx=4 : "Michele you did wrong" };
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arb_array[elements_in_layer].in1 = channels[inputs_in_layer];
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arb_array[elements_in_layer].in2 = channels[inputs_in_layer+1];
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inputs_in_layer = end;
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[] else ->
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//If we are not close to the end, analyzes the next two inputs
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arb_array[elements_in_layer].in1 = channels[inputs_in_layer];
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arb_array[elements_in_layer].in2 = channels[inputs_in_layer+1];
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inputs_in_layer = inputs_in_layer +2;
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]
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elements_in_layer = elements_in_layer + 1; //At every step the elements count is updated
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]
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//Move the inputs_in_layer to the next layer
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//Increase the end to account for the next layer elements
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//If there was an odd element, count it also in the end
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inputs_in_layer = end + 1;
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end = end + elements_in_layer + odd_element_flag;
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element_counter = element_counter + elements_in_layer;
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]
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}
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export template<pint N>
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export template<pint N>
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defproc merge (avMx1of2<N> in1; avMx1of2<N> in2; avMx1of2<N> out ; bool? reset_B; power supply) {
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defproc merge (avMx1of2<N> in1; avMx1of2<N> in2; avMx1of2<N> out ; bool? reset_B; power supply) {
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